Difference between revisions of "User:Meikebrand"

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<center>
  
== <font color="#FE2EF7"> HOMEWORK -1-  </font> ==
 
  
'''''Circuit with one resistor'''''
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https://media.giphy.com/media/bSToG7lsB1vB6/giphy.gif
  
Brown, green, red, gold
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<b>
:First digit=1, second digit=5, multiplier 100, tolerance= 5%
 
:15x100=1500 1,5 k ohms
 
  
:R = V/I 9 V : 6 I = 1,5 kilo ohms
 
:I = V/R 9 V : 1,5 ohms = 6 ampere
 
:V = IxR 6 x 1,5 = 9 V
 
:6 x 1,5 ohms = 9
 
:9 volt battery
 
  
'''What is the voltage across the resistor'''
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<font color="#FF36FD"> ___________________________________ </font>
:Voltage drop is 0,1,4 V
 
'''What is the current through the resistor'''
 
:6 amp
 
'''What happens to the current and voltage if you double the resistor value'''
 
:Current stays the same and voltage doubles
 
'''What happens to the current and voltage if you half the resistor value'''
 
:Current stays the same and voltage is split in half
 
  
  
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https://wmbgrad17.tumblr.com/
  
'''''Circuit with two resistors'''''
 
  
Brown, black, orange, gold
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[[/UTC | <font color="#BB00C8"> MINOR  </font>]]
:First digit=1, second digit=0, multiplier 1, tolerance= 5%
 
:1. x100=10 k ohms
 
:9 volt battery
 
  
:R = V/I 9 V : 6 I = 10 kilo ohms
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[[/UTC | <font color="#A10B9E">  UNRAVEL THE CODE Q10 </font>]]
:I = V/R 9 V : 10 ohms = 0,9 ampere
 
:V = IxR 6 x 1,5 = 9 V
 
:Voltage drop = 0,9 x 10 ohms = 9
 
  
'''What is the voltage across each resistor'''
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[[/CFM | <font color="#9400D3">  CRAFTING FUTURE MEMORIES  </font>]]
:Voltage drop is 9
 
'''What is the current through each resistor'''
 
:9 amp
 
'''What happens to the current and voltage if you double the resistor value of one resistor'''
 
:Current stays the same and voltage doubles
 
  
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[[/UTI | <font color="#A10B9E"> UNRAVELING THE INFRA-ORDINARY  </font>]]
  
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[[/UTM | <font color="#BB00C8">  MEME  </font>]]
  
'''''Circuit with three or more series resistors'''''
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[[/ETT| <font color="#FF36FD">  EXPANDING THE TOOLBOX  </font>]]</b>
 
 
Orange, orange, orange, gold
 
:First digit=3, second digit=3, multiplier 1, tolerance= 5%
 
:3.3x100=33 k ohms
 
:9 volt battery
 
 
 
:R = V/I 9 V : 0,27 I = 33 kilo ohms
 
:I = V/R 9 V : 33 ohms = 0,27 ampere
 
:V = IxR 0,27 x 33 = 9 V
 
:Voltage drop = 0,27 x 33 ohms = 8,91 drop
 
 
 
'''What is the voltage across each resistor'''
 
:Voltage drop is 8,9
 
'''What is the current through each resistor'''
 
:9 amp
 
'''What happens to the current and voltage if you double the resistor value of one resistor'''
 
:Current stays the same and voltage doubles
 

Latest revision as of 11:10, 17 February 2017